2(x^2+5)=x(2x+5)

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Solution for 2(x^2+5)=x(2x+5) equation:


Simplifying
2(x2 + 5) = x(2x + 5)

Reorder the terms:
2(5 + x2) = x(2x + 5)
(5 * 2 + x2 * 2) = x(2x + 5)
(10 + 2x2) = x(2x + 5)

Reorder the terms:
10 + 2x2 = x(5 + 2x)
10 + 2x2 = (5 * x + 2x * x)
10 + 2x2 = (5x + 2x2)

Add '-2x2' to each side of the equation.
10 + 2x2 + -2x2 = 5x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
10 + 0 = 5x + 2x2 + -2x2
10 = 5x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
10 = 5x + 0
10 = 5x

Solving
10 = 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.
10 + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
10 + -5x = 0

Add '-10' to each side of the equation.
10 + -10 + -5x = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -5x = 0 + -10
-5x = 0 + -10

Combine like terms: 0 + -10 = -10
-5x = -10

Divide each side by '-5'.
x = 2

Simplifying
x = 2

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